a) y =
(x + C1)3 + C2; b) y = ln |C1ex - 1/(C1ex)| + C2, y = ±x + C;
°c) y = C1 e-x (x + 1) + C2; d) y = (C1x - C
)ex/C1+1 + C2; °e) y2 = C
+ (x + C2)2/C
;
f) x + C2 = ±
(
- 2C1)
; °g) y = ln(2C
) + C1x + C2 - 2 ln |eC1x+C2 - 1|,
y = ln (2C
) - 2 ln | cos(C1x + C2)|, °y = 2 ln(
/|x + C|); °h) y = (1/C1) cosh(C1x + C2);
i) y = C1 / cos 2(x + C2); j) C1y + (1 + C
) ln |y - C1| = x + C2.